Texas Electrician ExamTexas journeyman & master

Voltage drop is tested, and it is not a code rule

Knowing that distinction is worth a point on its own, because questions are written to see whether you treat a recommendation as a mandate.

On this page
  1. Start with what it is not
  2. Why it still gets tested constantly
  3. The arithmetic
  4. The two directions a question can run
  5. What people get wrong
  6. How to hold it in your head
  7. What this page cites

Start with what it is not

The length in a voltage drop calculation is the round trip, not the distance on the drawing A supply feeds a load two hundred feet away. Current travels out on one conductor and back on the other, so the conductor length in the calculation is four hundred feet for a single phase circuit. Using the one way distance halves the answer and is the most common error on this type of question. Three phase circuits use a different multiplier for the same physical reason. supply load out back 200 ft 200 ft out + 200 ft back the conductor in the formula is 400 ft the tape measure says one number, the formula wants another
One way on the tape measure, two ways in the formula. This single mistake halves more answers than any other. Voltage drop is an Informational Note, at 210.19 for branch circuits and 215.4(A)(2) for feeders, not a requirement. Exams still ask it.

For general branch circuits and feeders, the code does not set an enforceable voltage drop limit. The familiar figures appear in informational notes.

An informational note is explanatory. It is not an enforceable part of the code, and the code says so about its own notes.

That is the trap. A question can ask what the code requires, and the correct answer for an ordinary branch circuit is that it does not require a specific voltage drop percentage.

There are places where a performance requirement does exist, notably for specific equipment and specific systems. Those are separate rules, in their own articles, and they are enforceable where they apply.

Why it still gets tested constantly

Because it is real engineering, and because a conductor that meets ampacity can still deliver unusable voltage at the far end of a long run.

Motors are the usual case. Undervoltage at start means the motor draws more current, heats up, and can fail to come up to speed. Nothing in the ampacity calculation catches that.

So the exam tests the arithmetic even where the code does not compel the outcome.

The arithmetic

Voltage drop is current times resistance. Everything else is bookkeeping about how the resistance is expressed and how many conductors the current travels through.

The resistance values live in Chapter 9. Look them up in your own book rather than working from a remembered figure, because they differ by material and by conductor construction.

The two directions a question can run

Forward: given a conductor, a length and a load, what is the voltage drop? Straight substitution.

Backward: given a maximum acceptable drop, what conductor do you need? Rearrange for resistance, then find the first conductor whose resistance is at or below that. This is the harder version and the more common one.

On the backward version, the answer is a conductor size, so you round to a real conductor and you round in the direction that reduces resistance, which means going larger.

What people get wrong

The first two are the same error in different clothes: not thinking about the actual path the current takes.

How to hold it in your head

Do not memorize a formula with letters in it. Remember the sentence: current times the resistance of the path, and the path is longer than the run.

From there you can rebuild any version of the calculation under pressure, including the backward one, without needing to remember which letter stood for what.

What this page cites

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